Question 947450
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I'm afraid your answer is not correct.
Here is a step-by step solution.

{{{9x^4-6x^3+18x^2-12x}}}

Factor 3x out of all terms:

{{{3x(3x^3^""^""-2x^2+6x-4)}}}

Factor x<sup>2</sup> out of the first two term in parentheses
and +2 out of the last two terms in parentheses:

{{{3x(x^2^""^""(3x^""-2)^""+2(3x^""-2))}}}

Now we have a common factor of (3x-2),
so we factor it out inside the parentheses:

{{{3x((3x^""-2)^""^""(x^2+2))}}}

Now we can drop the bigger parentheses:

{{{3x(3x^""-2)^""^""(x^2+2)}}}