Question 947456
Distance = Speed * Time

You know the distance is the same going both ways. You are given the speed both ways and a relationship of the time.

Let T be the number of hours outbound

DistanceOut = SpeedOut * timeOut
DistanceOut = 30*T

time coming back is 1 hour less than time going out = T-1
DistanceBack = SpeedBack * TimeBack
DistanceBack = 50 * (T-1)

Distance is the same both ways. So
{{{30 * T = 50 * (T-1)}}}
{{{30T = 50T - 50}}}
{{{-20T = -50}}}
{{{T = 5/2}}}


So the time outbound is 5/2 hours = 2.5 Hours
Which says the time back is 1.5 hours.

To check your answer, does 30*2.5 = 50*1.5 ??


Get it now??

Now go out and have some fun this weekend!