Question 947431
Given csc theta = 27, use trigonometric identities to find the exact value of sec^2 theta. Completely simplify your answers.
-----
csc = r/y
r = 27 ; y = 1
------
x = sqrt[27^2-1] = sqrt(728) = sqrt(16*9*5) = 12sqrt(5)
-----
sec = x/r = 12sqrt(5)/27
-----
Ans: sec^2(t) = [12sqrt(5)/27]^2 = 728/729
---------------
Cheers,
Stan H.
----------------