Question 947406
x^(2/3) - 5x^(1/3) + 6 = 0
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Let w = x^(1/3)
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Rewrite the quadratic::
w^2 - 5w + 6 = 0
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Factor::
(w-6)(w+1) = 0
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w = 6 or w = -1
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Solve for "x"::
If w = 6, x^(1/3) = 6 ; x = 6^3 = 216
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If w = -1, x^(1//3) = -1 ; x = (-1)^3 = -1
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Cheers,
Stan H.
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