Question 947354
Find the hypotenuse using the Pythagorean theorem,
{{{8^2+8^2=H^2}}}
{{{H^2=2*8^2}}}
{{{H=8sqrt(2)}}}{{{cm}}}
The perimeter is then,
{{{P=8+8+8sqrt(2)}}}
{{{P=8(2+sqrt(2))}}}{{{cm}}}