Question 947367
Yes to both.


#1 is obvious because you solve for y in terms of x.


#2, less obvious.
{{{x+sqrt(y)=5}}}, one branch of a parabola.
{{{sqrt(y)=-x+5}}}, and you must have {{{y>=0}}}.
square both sides.
{{{y=(5-x)^2}}}, .


The part for which y is non-negative would be the actual graph.
{{{graph(300,300,-8,12,-8,12,(5-x)^2)}}}



Also multiply the right member.
{{{y=25-10x+x^2}}}
{{{y=x^2-10x+25}}}
and that is the same as {{{y=(x-5)^2}}}.