Question 947349
{{{x^(1/6)*x^(1/6)}}}
{{{x^(1/6+1/6)}}}
{{{x^(2/6)}}}
{{{x^(1/3)}}}


That shown above is not rendering to display well on my view.


Use this substitution:
{{{u=x^(1/6)}}}  and   this gives you {{{u^2=x^(1/3)}}}.


u=x^(1/6)   and   u^2=x^(1/3)



Jaime did not use the best choice for substitution.
Also remember, you are first solving for x^(1/6).