Question 1671
to amend the other solution...

{{{y=3(x-2)^2+6}}} is {{{y=3(x^2 - 4x + 4) + 6}}}, so it is {{{y=(3x^2-12x+12)+6}}} and hence {{{y=3x^2 - 12x + 18}}}. Then use your formula. It should be a nice number this time.

Jon