Question 80578
{{{49x^2+9=42x}}}
First, equate to zero and write it out in ax^2+bx+c form:
{{{49x^2-42x+9=0}}}
Apply the quadratic formula:
{{{x=42+-sqrt((42^2)-(4)(49)(9))/(2*49)}}}
Simplify and you can see the discriminant is zero. This means you only have one root to the equation, and leaves you with: 
{{{x=42/98}}}
You can reduce this:
{{{highlight(x=3/7)}}}
Good Luck,
tutor_paul@yahoo.com