Question 947205
Use logarithms to solve the equation

9(1.09^2x+1)=15

the 2x+1 is in expotential form  
If you mean it's an exponent:
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9(1.09^2x+1)=15
1.09^(2x+1)= 5/3
(2x+1)*log(1.09) = log(5/3)
2x+1 = log(5/3)/log(1.09)
x = (-1 + log(5/3)/log(1.09))/2