Question 947205
{{{9(1.09^(2x+1))=15}}}
{{{1.09^(2x+1)=15/9}}}
{{{1.09^(2x+1)=5/3}}}
{{{2x+1=log(1.09,(5/3))}}}
{{{2x=log(1.09,(5/3))-1}}}
{{{x=(1/2)(log(1.09,(5/3))-1)}}}
{{{highlight_green(x=(1/2)(log((5/3))/log((1.09)))-1/2)}}}
approximately,
{{{x=2.46}}}