Question 80546
7x+8overx+1 + 4x+3overx+1 add if possible simplify
:
{{{((7x+8)/(x+1))}}} + {{{((4x+3)/(x+1))}}}
:
They have the same denominator so can write it:
{{{((7x+8)+(4x+3))/((x+1))}}}
:
{{{(7x + 4x + 8 + 3)/((x+1))}}}; remove brackets, group like terms
:
{{{(11x + 11)/((x+1))}}}; add like terms
:
{{{(11(x + 1))/((x+1))}}}; factor out 11
:
(x+1)'s cancel, so ans = 11