Question 947170
{{{B=3A}}}
{{{C=7+A}}}
and
{{{A+B+C=62}}}
Substitute,
{{{A+3A+7+A=62}}}
{{{5A=55}}}
{{{A=11}}}
So then,
{{{B=3(11)}}}
{{{B=33}}}
and
{{{C=7+11}}}
{{{C=18}}}