Question 947131
F=fifties; TW=twenties=3F+3; T=tens=F+16
$50F+$20TW+$10T=$1660 Substitute and solve for F
$50F+$20(3F+3)+$10(F+16)=$1660
$50F+$60F+60+$10F+160=$1660 Subtract 220 from each side
$120F+220-220=$1660-220
$120F=$1440
F=12 ANSWER 1: There were 12 fifty dollar bills.
TW=3F+3=3(12)+3=36+3=39 ANSWER 2:There were 39 twenty dollar bills.
T=F+16=12+16=28 ANSWER 3: there were 28 ten dollar bills
CHECK
$50F+$20TW+$10T=$1660
$50(12)+$20(39)+$10(28)=$1660
$600+$780+$280=$1660
$1660=$1660