Question 947087
With 3 tosses, there are {{{6^3=216}}} possible outcomes
The only ones that show only even numbers are:
222,224,226,242,244,246,262,264,266
422,424,426,442,444,446,462,464,466
622,624,626,642,644,646,662,664,666
or 27 outcomes.
So the probability of getting at least one odd number is,
{{{P=(216-27)/216=189/216=7/8}}}