Question 947123
Jamie has 300 ft of fencing to enclose a rectangular pasture. The pasture's length is to be 10 ft less than 3 times the width. Find the width of the garden.
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 A. Write a system of equations for the problem.
Perimeter = 2(length + width)
300 = 2(3w-10 + w)
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 B. Solve your system.
150 = (4w-10
4w = 160
w = 40 ft (width)
Length = 3w-10 = 3*40-10 = 110 ft
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Cheers,
Stan H.
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