Question 946989

{{{tan(theta) -1 = (sin^2(theta)-cos^2(theta))/ (sin(theta)cos(theta)+cos^2(theta))}}}....{{{sin^2(theta)-cos^2(theta)=(sin(theta)-cos(theta))(sin(theta)+cos(theta))}}}


{{{tan(theta) -1 = (sin(theta)-cos(theta))(sin(theta)+cos(theta))/ (cos(theta)(sin(theta)+cos(theta)))}}}


{{{tan(theta) -1 = (sin(theta)-cos(theta))cross((sin(theta)+cos(theta)))/ (cos(theta)cross((sin(theta)+cos(theta))))}}}


{{{tan(theta) -1 = (sin(theta)-cos(theta))/ cos(theta)}}}


{{{tan(theta) -1 = sin(theta)/ cos(theta)-cos(theta)/ cos(theta)}}}


{{{tan(theta) -1 = tan(theta) -1}}}