Question 946969
The probability that a certain make of car will need repairs in the first six months is 0.27 . A dealer sells 5 such cars. What is the probability that at least one of them will require repairs in the first six months
---
Binomial Problem with n = 5 ; p(need repair) = 0.27 ; p(not need) = 0.73
--------------------
Ans: P(1<= x <=5) = 1 - P(x=0) = 1 - 5C0(0.27)^0*0.73^5 = 0.73^5 = 0.7927

=========================================================
 AND 
Luis has a coin that is weighted so that the probability that Heads appears when it is tossed is 0.52 . Suppose that the coin is tossed 4 times. What is the probability that all 4 tosses are Heads?
P(x = 4) = 0.52^4 = 0.0731
--------------
Cheers,
Stan H.
----------------