Question 947011
For a SPHERE with radius {{{r}}}, the volume and surface area
are found using:

{{{V=(4/3)pi*r^3}}}  and {{{SA=4pi*r^2}}}

if a surface area of {{{SA=196pi*mil^2}}} we can find radius {{{r}}}

{{{196pi*mil^2=4pi*r^2}}}

{{{(196cross(pi)*mil^2)/(4cross(pi))=r^2}}}

{{{(196mil^2)/4=r^2}}}

{{{49mil^2=r^2}}}

{{{r=sqrt(49mil^2)}}}

{{{highlight(r=7mil)}}} ..now plug it in {{{V=(4/3)pi*r^3}}} 

{{{V=(4/3)pi*(7mil)^3}}} 

{{{V=(4/3)*343pi*mil^3}}} 

{{{V=(1.3333333333333)343pi*mil^3}}} 

{{{V=457.3333333333219*pi*mil^3}}} 

{{{V=457.33pi*mil^3}}}