Question 946852
{{{3x^2-4=3x+14}}}
{{{3x^2-3x-18=0}}}
{{{x^2-x-6=0}}}
{{{(x-3)(x+2)=0}}}
First quadrant, x is positive.
{{{x-3=0}}}
{{{x=3}}}
The other solution would give you {{{x=-2}}} which is not in the first quadrant.