<PRE><B>Question 946776</B>
Two ships leaves the same port at 7 AM, the first ship sails on a 54 degree course at constant rate of 36 MPH, the second ships sails on a 144 degree course at a constant rate or 42 MPH.
 How far from each other are the two ships at 11 AM?
:
The angle formed by the paths of the two ships: 144- 54 = 90 degrees
The distance between the two ships will be the hypotenuse of a right triangle
The travel time of the ships, 11 - 7 = 4hrs
The distance traveled by the two ships: Dist = speed * time
36 * 4 = 144 miles
and
42 * 4 = 168 miles
d = {{{sqrt(144^2 + 168^2)}}}
d = 221.27 mi apart</PRE>