Question 946724
{{{(A+B+C+D+E)/5=8}}}
1.{{{A+B+C+D+E=40}}}
.
.
{{{(A+B)/2=5}}}
2.{{{A+B=10}}}
Subtracting eq.2 from eq.1,
{{{A+B+C+D+E-A-B=40-10}}}
{{{C+D+E=30}}}
So,
{{{(C+D+E)/3=highlight(10)}}}