Question 946706
Let the length of the rectangle be x.
Width of the rectangle=2x-5
Area of the rectangle=x(2x-5)
x(2x-5)=122
2x^2-5x-122=0
x^2-2.5x-61=0
*[invoke quadratic "x", 1, -2.5, -61 ]
x=9.16
2x-5=13.32
Length of the diagonal=16.16