Question 946622
The point (-3/5, y) in the third quadrant corresponds to angle θ on the unit circle.
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r = sqrt[y^2-(3/5)^2] = sqrt[(25y^2-9)/25]
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 The value of sec θ is ?
sec(t) = x/r = (-3/5)/sqrt[(25y^2-9)/25]
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the value of cot θ is ?
cot(t) = x/y = (-3/5)/y = -3/(5y)
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Cheers,
Stan H.
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