Question 946643
Solve for a in log(2a)- 3log2= 1/2log(a-3)
log(2a)- 3log2= 1/2log(a-3)
log(2a/(2^3))=log((a-3)^(1/2))
2a(2^3)=(a-3)^(1/2)
16a=√(a-3)
square both sides:
256a^2=a-3
256a^2-a+3=0
b^2-4ac<0
no real solution