Question 946611
You are showing that you want this equation to be all in symbols, or almost all in symbols.


The leakage rate is  {{{(3/4)g/t}}}, or the ratio of the amount of volume leaked to the time that the leaking occurred.  Simplified, that is {{{(3/(4t))g}}} or  {{{(3/4)(g/t)}}}.   Before continueing this way, I am changing to 6=t, because otherwise I would confuse the further uses of the variables, including t.  I am now choosing to use the known given constant value.  The leak rate is {{{(3/4)(g/6)}}}.


This uniform rates problem seems to be a fairly simple linear equation application.  For time t=0, the volume in the tank is h=g.
For time t=6 or anything more than zero  (as long as not too large), the volume in the tank becomes {{{highlight(h=g-(3/4)(g/6)t)}}}.
Here, {{{t}}} is a variable, greater than or equal to zero and less than or about equal to 8 hours.  After about 8 hours, the tank would become empty, so no more leaking.