Question 946490
{{{(x^2 y^3)^3 (x^(a)y^2)=x^8y^(4c-1)}}}

{{{(x^6y^9)(x^(a)y^2)=x^8y^(4c-1)}}}
{{{x^(6+a)y^(9+2)=x^8y^(4c-1)}}}
{{{x^(6+a)y^11=x^8y^(4c-1)}}}
So,
{{{6+a=8}}}
{{{a=2}}}
and
{{{4c-1=11}}}
{{{4c=12}}}
{{{c=3}}}
So,
{{{2^(a+c)=2^(2+3)=2^5=32}}}