Question 946576
y^2+3y-10 0ver 3y+15 divided by (10-5y)=?
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(y^2+3y-10)/(3(y+5)) / (5(2-y))
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Factor::
[(y+5)(y-2)/(3(y+5))] / (-5(y-2))
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Cancel (y+5) and (y-2) to get::
= -1/15
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Cheers,
Stan H.
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A. 1/15
 B. -1/15
 C. -1/5