Question 946540

A square has a perimeter of {{{P=64ft}}} and an area of {{{A=256ft^2}}}. 

{{{P=4a}}}
{{{4a=64ft}}}
{{{a=64ft/4}}}
{{{a=16ft}}}

if the side length of the square is divided by {{{2}}}, then we have

{{{(a/2)=16ft/2}}}

{{{a/2=8ft}}} then the area and perimeter of the new square will be:

 {{{P=4(a)}}} will be {{{1/2}}} of {{{P=64ft}}}:

 {{{P=4*8ft}}}=>{{{P=32ft}}} which is {{{(1/2)64ft}}}


{{{A=256ft^2}}}

{{{a/2=8ft}}} then {{{A=(a/2)^2=(1/4)a^2}}}=> will be {{{1/4}}} of {{{A=256ft^2}}}:

 {{{A=(a/2)^2}}} will be {{{A=(8ft)^2}}}=>{{{A=64ft^2}}} and {{{64ft^2=(1/4)256ft^2}}}