Question 946420
if (1,0) is in the equation, then (0,1) must be in the inverse equation.


f(x) = log(x) becomes 0 = log(1) through the point (1,0).


f^-1(x) = 10^x becomes 1 = 10^0 through the point (0,1).


you can see from the graph below that the point (1,0) is on the grpah of y = log(x) and the point (0,1) is on the grpah of y = 10^x.


<img src = "http://theo.x10hosting.com/2015/021001.jpg" alt="$$$" </>