Question 946472
Look at all possible outcomes, there are {{{6^2=36}}} of them.
1-1 1-2 1-3 1-4 1-5 1-6
2-1 2-2 2-3 2-4 2-5 2-6
3-1 3-2 3-3 3-4 3-5 3-6
4-1 4-2 4-3 4-4 4-5 4-6
5-1 5-2 5-3 5-4 5-5 5-6
6-1 6-2 6-3 6-4 6-5 6-6
Of those 36, 6 of them sum to 7.
1-6 2-5 3-4 4-3 5-2 6-1
So,
{{{P=6/36=1/6}}}