Question 946390
I am given the equation f(x)=300x-11x squared +2. I am asked to find the maximum. Normally the homework problems show step by step instruction although this one isn't. Can you please help we with this
<pre><font face = "Tohoma" size = 4 color = "indigo"><b>These sure are some big numbers that don't seem to cancel. Are you sure you submitted the problem correctly?
{{{f(x) = 300x - 11x^2 + 2}}}_____{{{f(x) = 2 + 300x - 11x^2}}}
The maximum occurs at the x coordinate of the vertex, or at {{{x = - b/(2a)}}}, or {{{x = - 300/(2 * - 11)}}}, or {{{x = (- 300)/(- 22)}}}, or {{{x = 150/11}}}
{{{f(x)_or_y = 2 + 300x - 11x^2}}} 
{{{f(x)_or_y = 2 + 300(150/11) - 11(150/11)^2}}} ----- Substituting {{{x = 150/11}}}, where the maximum occurs 
{{{f(x)_or_y = 2 + (45000/11) - 11(22500/121)}}} 
{{{f(x)_or_y = 2 + (45000/11) - (22500/11)}}} 
{{{f(x)_or_y = (22/11) + (45000/11) - (22500/11)}}} 
Maximum occurs at: {{{f(x)_or_y = 22522/11}}}, or {{{highlight_green(y = 2047.454545)}}} &#8776; 2047.<span style="text-decoration: overline">45</span>
You can do the check!! 
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