Question 946160


if the length {{{L}}} of a rectangle is {{{40}}}% more than its width {{{W}}}, then we have
{{{L=W+(40/100)W}}} 
{{{L=W+0.40W}}} 
{{{L=1.40W}}} 

 if its area is {{{560cm^2}}}, then

{{{560cm^2=L*W}}}.....substitute {{{L}}}

{{{560cm^2=1.40W*W}}}

{{{560cm^2=1.40W^2}}}

{{{560cm^2/1.40=W^2}}}

{{{400cm^2=W^2}}}

{{{W=sqrt(400cm^2)}}}

{{{highlight(W=20cm)}}}

now find the length:

{{{L=1.40W}}} 

{{{L=1.40*20cm}}} 

{{{highlight(L=28cm)}}}