Question 946012
The sum of the measures of the exterior angles is {{{360^o}}} >
(It is so because each exterior angle is the angle that your direction changes at a vertex as you go around the polygon,
and one turn around the polygon is a {{{360^o}}} turn).
If the sum of the measures of a polygon's interior angles is twice the sum of the measures of its exterior angles, then it is
{{{2*360^o=red(720^o)}}} 
The sum of the measures of the interior angles of a polygon depends on the number of sides of the polygon, {{{n}}} ,
and is {{{green((n-2)*180^o)}}} .
For this problem,
{{{green((n-2)*180^o)=red(720^o)}}}--->{{{n-2=720^o/180^o}}}--->{{{n-2=4}}}--->{{{n=4+2}}}--->{{{highlight(n=6)}}}