<PRE><B>Question 945924</B>
Graph y1=6^3x+1 and y2=215 find the point of intersection. I know y = 215
:
 a graphing table to plot this:
 x | y
-------
 0 | 2
.2 | 3.9
.4 | 9.6
.6 | 26
.8 | 74.7
1.0| 217, exceeds 215
looks like this
{{{ graph( 300, 200, -1, 2, -100, 300, 6^(3x)+1, 215)}}}
:
find out what x is when y = 215
{{{6^(3x)+1 = 215}}}
Subtract 1 from both sides
{{{6^(3x) = 214}}}
{{{log((6^(3x))) = log((214))}}}
log equiv of exponents
{{{3x*log((6)) = log((214))}}}
3x = {{{log((214))/log((6))}}}
using the calc
3x = 2.9948
x = {{{2.9948/3}}}
x = .99827, almost 1, agrees with the graph

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