Question 945809
For the first pick,
there is a total of {{{6+8+6=20}}} socks in the drawer.
and only {{{8}}} of them are black,
so the chance of getting a black sock is {{{8/20=2/5}}} .
So you would get a black sock {{{2/5=40/100="40%"}}} of the time.
In the {{{2/5=40/100="40%"}}} of the cases when your first pick was a black sock,
you would have {{{8-1=7}}} black socks left,
in a drawer containing a total of {{{20-1=19}}} socks.
In that case, the chance of getting a black sock for the second pick is {{{7/19=about}}}{{{0.3684}}} .
So, the overall fraction of the times that you would get two black socks out of the drawer on consecutive picks is
{{{7/19}}} of {{{2/5=40/100="40%"}}} of the cases, or
{{{(7/19)*(40/100)=about}}}{{{0.3684*(40/100)=14.736/100=about}}}{{{15/100=highlight("15%")}}} (rounding to the nearest whole percent).