Question 80419
{{{(1/7)^x = 49}}}
note that
{{{49 = 7^2}}}
so
{{{(1/7)^x = 7^2}}}
also note
{{{(1/7)^x = 1/(7^x)}}}
now I have
{{{1/(7^x) = 7^2}}}
You should know that
{{{1/(7^x) = 7^(-x)}}}
now I have
{{{7^(-x) = 7^2}}}
{{{-x = 2}}}
{{{x = -2}}} answer