Question 945773
Log2^x+log4^x+log8^x=21/4, find x
{{{log((2^x*4^x*8^x))=21/4}}}
{{{log((2^(x)*2^(2x)*2^(3x)))=21/4}}}
{{{log((2^(6x)))=21/4}}}
{{{6xlog(2)=21/4}}}
6x=21/4log2
x=21/(24log2)
x≈2.9067