Question 945751
{{{x^2/((x^2-4))}}} * {{{((x+2))/x}}}
the first denominator is the difference of squares, factors to
{{{x^2/((x-2)(x+2))}}} * {{{((x+2))/x}}}
Cancel (x+2)
{{{x^2/((x-2))}}} * {{{1/x}}}
Cancel x into x^2
{{{x/((x-2))}}} is lowest terms