Question 945735
Twice the sum of two consecutive even numbers is {{{52}}}.

We can do this by letting the first number be {{{2x}}} instead of {{{x}}}. What would the next consecutive even number be? Be careful. {{{2x + 1}}} is not even.
 So, our next numbers would be {{{2x + 2}}} ,{{{ 2x + 4}}}. 

Similarly, consecutive odd numbers would be of the form {{{2x + 1}}}, {{{2x + 3}}}, etc.


Twice the sum of two consecutive even numbers, {{{2x}}} and {{{2x+2}}} is {{{52}}}:

{{{2(2x+(2x+2))=52}}}....solve for {{{x}}}

{{{2(2x+2x+2)=52}}}

{{{2(4x+2)=52}}}

{{{8x+4=52}}}

{{{8x=52-4}}}

{{{8x=48}}}

{{{x=48/8}}}

{{{x=6}}}

so, 

the first even number is {{{2x}}}=>{{{2*6}}}=>{{{12}}}

the second even number is {{{2x+2}}}=>{{{2*6+2}}}=>{{{14}}}