Question 945600
find the derivative of the following function using the limt defintion 
((x-1)^2)/(x)
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= (x^2 - 2x + 1)/x
= x - 2 + (1/x)
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You can probably do the x term --> 1
The -2 --> 0
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That leaves 1/x
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(1/(x+h) - 1/x)/h = (x - (x+h))/(h*(x^2 + hx))
= -h/(h*(x^2 + hx))
= -1/(x^2 + hx)
Lim = -1/x^2
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--> 1 - (1/x^2)
or (x^2 - 1)/x^2