Question 945439
1.{{{A+B+C=168}}}
.
.
{{{(A-6)/(B-6)=2/3}}}
{{{3(A-6)=2(B-6)}}}
{{{3A-18=2B-12}}}
2.{{{3A-2B=6}}}
.
.
{{{(B-6)/(C-6)=3/5}}}
{{{5(B-6)=3(C-6)}}}
{{{5B-30=3C-18}}}
3.{{{5B-3C=12}}}
From the eq. 1,
{{{C=168-A-B}}}
Substitute into eq. 3,
{{{5B-3(168-A-B)=12}}}
{{{5B-504+3A+3B=12}}}
4.{{{3A+8B=516}}}
Now subtract eq. 2 from eq. 4,
{{{3A+8B-3A+2B=516-6}}}
{{{10B=510}}}
{{{B=51}}}
Then,
{{{3A+8(51)=516}}}
{{{3A+408=516}}}
{{{3A=108}}}
{{{A=36}}}
and
{{{A+B+C=168}}}
{{{36+51+C=168}}}
{{{87+C=168}}}
{{{C=81}}}