Question 945496
Use the Pythagorean theorem,
{{{L^2+(2L+20)^2=(2L+22)^2}}}
{{{L^2+4L^2+80L+400=4L^2+88L+484}}}
{{{L^2-8L-84=0}}}
{{{(L-14)(L+6)=0}}}
Use only the positive solution.
{{{L-14=0}}}
{{{L=14}}}
So then,
{{{L[2]=20+2(14)}}}
{{{L[2]=20+28}}}
{{{L[2]=48}}}
and
{{{L[3]=22+2(14)}}}
{{{L[3]=22+28}}}
{{{L[3]=50}}}