Question 945501
1.{{{A+B+C=27}}}
2.{{{A+B=C+83}}}
3.{{{C=A-60}}}
Substitute eq. 3 into eqs. 1 and 2,
{{{A+B+A-60=27}}}
3.{{{2A+B=87}}}
.
.
{{{A+B=A-60+83}}}
4.{{{B=23}}}
So then substituting into eq. 3,
{{{2A+23=87}}}
{{{2A=64}}}
{{{A=32}}}
and finally,
{{{32+23+C=27}}}
{{{C=-28}}}