Question 945475
let A=the first integer
(A)(A+2)=3(A+2)+126
(A)(A+2)=3A+6+126
A^2+2A-3A-6-126=0
A^2-A-132=0
*[invoke quadratic "x", 1, -1, -132]
Answers 12,-11 Even result=12
ANSWER 1: The first integer is 12
A+2=12+2=14 ANSWER 2: The second integer is 14
CHECK
(12)(14)=3(14)+126
168=42+126
168=168