Question 945475
{{{N(N+2)=126+3(N+2)}}}
{{{N(N+2)-3(N+2)=126}}}
{{{(N-3)(N+2)=126}}}
{{{N^2-N-6=126}}}
{{{N^2-N-132=0}}}
{{{(N+11)(N-12)=0}}}
Only solving for even solution.
{{{N-12=0}}}
{{{N=12}}}
So the two integers are 12 and 14.