Question 944327
I'm assuming that the diameter of the semi-circle is the length of the rectangle.
The rectangular portion of the prism would have surface area of,
{{{A[r]=2*20*5+2*3*5+20*3=200+30+60=290}}}
The semi-cylindrical portion of the prism would have a surface area of,
{{{A[c]=2*((pi(10^2))/2)+(2pi*10*3)/2=100pi+30pi=130pi}}}
So then the total area is,
{{{A=290+130pi}}}