Question 945407
They take two different numbers,{{{x}}} and {{{y}}}.
The first girl finds half the sum of the numbers and divides her answer by {{{3}}}. 

{{{((x+y)/2)/3}}}


{{{((x+y)/2)/(3/1)}}}


{{{(x+y)/6}}}

The second girl, multiplies the sum of the numbers by {{{3}}} and divides her answer by {{{2}}}.
 
{{{3(x+y)/2}}}

They then divide the first girl's answer by the second girl's answer 


{{{((x+y)/6)/(3(x+y)/2)}}}


{{{(2(x+y))/(6*3(x+y))}}}


{{{(cross(2)1cross((x+y)))/(cross(6)3*3cross((x+y)))}}}


{{{1/9}}}-> your answer