Question 945331
solve for x
{{{ log3 (x-9) + log3 (x-3)=2 }}}
{{{ log(3,((x-9)(x-3)))=2}}}
3^2=(x-9)(x+3)
9=x^2-6x-27
x^2-6x-36=0
solve by quadratic formula: 
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
a=1, b=-6, c=-36
ans:
x=-3.7 (reject)
or
x=9.7