Question 945260
  
Given:
5 apples, 4 peaches and 3 pears.
Find probability of randomly picking 3 fruits that are different.
  
Solution:
Denote {{{nCr=n!/((n-r)!*r!)}}}
Number of ways of arranging 5 apples, 4 peaches and 3 pears = {{{12C3=220}}}
Number of ways of arranging 3 different fruits = {{{5C1 * 4C1 * 3C1 = 5*4*3 = 60 }}}
Probability of picking 3 fruits that are different = {{{60/220=3/11}}}
  
Answer:
Probability of randomly choosing 3 fruits that are different = {{{3/11}}}